Hey, guys, I have a good idea!

[Loaden]

For example this code, 'p' is a pointer, and 'a' is a value.
If type "p." or "a.", they show the same results.

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#include <iostream>

class A
{
public:
   A();
   ~A();

   void testMsg() {}

private:
   int iLoveYou;
};

int main()
{
   A* p = new A;
   A a;
   a.testMsg();
   return 0;
}


Because CC can identified a pointer, or value, so we can do that:
If it is a pointer, then automatically replace from "." to  "->", like this:
form:

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p.testMsg();
to:

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p->testMsg();

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[TerryP]

Useful, might I also suggest handling an accidental ',' as well?

*groans* I still remember spending trying to figure out a compiler error, over an x,y typo, after an 8~12 hour straight coding run.

[ollydbg]

blueshake has suggested that feature before, but there are objections.

[Loaden]

blueshake has suggested that feature before, but there are objections.

But such tips is clearly a very ridiculous!
p.testMsg();

Code Select Expand

int main()
{
   A* p = new A;
   p.testMsg();
   return 0;
}

Both of "Qt Creator" and "Visual Assist X" selected from the "." To "->" conversion.
I hope CC team to re-consider this feature.
Thanks!

[nanyu]

but how about the "smart pointer"?

std::auto_ptr<MyStruct>  ap (new MyStruct());

ap. ?? //now the cc show thoese tips:
     release()
     get()

ap->  //show nothing.

[blueshake]

"Qt Creator"

@Loaden

since Qt Creator can do this , I think cc can do this in the future too.

[oBFusCATed]

but how about the "smart pointer"?

std::auto_ptr<MyStruct>  ap (new MyStruct());

ap. ?? //now the cc show thoese tips:
     release()
     get()

ap->  //show nothing.

CC Doesn't support operator overloading