Getting the file path

[threeS]

Good day!
In relation to my post previously in:

http://forums.next.codeblocks.org/index.php/topic,19604.new.html#new

How can i get the file path of my compiled program using my build plugin.
The events already works every time i hit compile button.

thank you for the response.

[oBFusCATed]

Checkout the cbProject and CompileTargetBase classes.

[threeS]

Good day!

We had tried some experiments like

-

Manager::Get()->GetProjectManager()->GetActiveProject()->GetFilename()

Returned output:

/file/project/location/file.cbp

(It returns the cbp file)

-

Manager::Get()->GetProjectManager()->GetActiveProject()->GetActiveBuildTarget()

Returned output:

default

-

Manager::Get()->GetProjectManager()->GetActiveProject()->GetBasePath()

Returned output:

/file/project/location/

(It returns the project path)

-

Manager::Get()->GetProjectManager()->GetActiveProject()->GetCurrentlyCompilingTarget()->GetFilename()

Returned output: (codeblocks crashes along with codeblocks debug file)

We're trying to get the file path of the compiled file but we have no luck on finding it.,
Expected:

/file/project/location/file.cpp

[attachment deleted by admin]

[oBFusCATed]

What about the CompileTargetBase::GetOutputFilename?

[threeS]

We've tried the

CompileTargetBase::GetOutputFilename

but it gives the output

/file/project/location

.


Anybody can help?  :'(

[oBFusCATed]

What object have you used as this project or a target?

[threeS]

We don't really know what you mean but we are creating a plugin. 

[threeS]

After a lot of trials and errors, we derive on these one:

wxString activetarget = Manager::Get()->GetProjectManager()->GetActiveProject()->GetActiveBuildTarget();

    wxString outputfile = Manager::Get()->GetProjectManager()->GetActiveProject()->GetBuildTarget(activetarget)->GetOutputFilename();
    wxString basepath = Manager::Get()->GetProjectManager()->GetActiveProject()->GetBasePath();
    wxString executable = basepath  + outputfile;
    executable.replace(executable.find(_(".")), 4,_(".cpp"));

and we successfully get what we're looking for, getting the

/file/project/location/file.cpp

.
thanks a lot 

[oBFusCATed]

I don't know what project you have loaded, but this is the output for the following script run when the codeblocks-unix.cbp project is open:

Code Select Expand


> print(GetProjectManager().GetActiveProject().GetBuildTarget(_T("src")).GetOutputFilename())
devel/codeblocks


Have you search the code of C::B to see how GetOutputFilename is used?