code complete cannot list the lua's function

[momocc]

my codeblocks cannot list the functions of lua.
i try to find out the reason why codeblocks cannot do it.
i found that there is a small difference between lua's function declaration and our usual practice.

Usually, we define a function like this:

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void func(); ???
but the defination in lua is:

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void (func)();

so, the code completion cannot recognize the functions..
if i remove the brackets, the code completion will list the function name correctly

[ollydbg]

Code::Blocks is a C/C++ IDE, and its codecompletion parser is also for C/C++ currently.
Lua language is not supported right now.

BTW: There is a FORTRAN codecompletion plugin for FORTRAN language. So we welcome user contribution for lua language.

[momocc]

Oh, the way i expressed has some wrong, i mean the code completion cannot list the functions of lua's C API.
i am doing a lua binding library for c++, so i often need to call the lua's C API to achieve some features

[ollydbg]

Oh, the way i expressed has some wrong, i mean the code completion cannot list the functions of lua's C API.
i am doing a lua binding library for c++, so i often need to call the lua's C API to achieve some features

Still not clear about your idea. If you would like to show C API, should should have C code parsed by the CC's parser. Where is you C API declaration? Please give more details.

[jarod42]

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int (bar_not_visible)();
int bar_visible();

void foo()
{
    ba|Ctrl+Space
}

code completion (for ba ) suggests only bar_visible, and not bar_not_visible.

[ollydbg]

Ok, does it a .c file?
Another question is:

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int (bar_not_visible)();

Do you think this is a valid C function declaration? I don't.

[Freem]

It is an uncommon style, but I think it is valid.

In short, when you declare a callback, you declare a function pointer. So, a pointer which know the address of a function (I know that you perfectly know that, I am just going step by step to make things clear as best as I can).

For a classic variable, we use this:

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int foo;
For a classic pointer:

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int *pfoo;[code]

For function pointers:
[code]int (*pbar)(void);
So there are no reasons to think removing the pointer operand is not legal.
In fact, we could probably say that removing parenthesis is just a shortcut for easier read, and the parenthesis write is the good one.

To conclude, I have tried a very little program (which do nothing) and compiled it with "gcc foo.c -ansi" and it gaves me no error or warning.
Here it is:

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int (bar_not_v)();
int (bar_v)();

void main()
{
bar_v();
bar_not_v();
}

int bar_not_v()
{
}

int (bar_v)()
{
}

[/code][/code]

[momocc]

Oh, the way i expressed has some wrong, i mean the code completion cannot list the functions of lua's C API.
i am doing a lua binding library for c++, so i often need to call the lua's C API to achieve some features

Still not clear about your idea. If you would like to show C API, should should have C code parsed by the CC's parser. Where is you C API declaration? Please give more details.

the C API declarations are in the Lua's header files
for example:

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// in lua.h
LUA_API lua_State *(lua_newstate) (lua_Alloc f, void *ud);